Respuesta :
Answer:
We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat
Explanation:
Step 1: Data given
Density of benzene = 0.88 g/mL
Molar mass of benzene = 78.11 g/mol
Heat produced = 1.5 * 10³ kJ
Step 2: The balanced equation
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ
Step 3: Calculate moles of benzen
1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6
Step 4: Calculate mass of benzene
Mass benzene : moles benzene * molar mass benzene
Mass benzene= 0.478 * 78.11 g
Mass of benzene = 37.34 grams
Step 5: Calculate volume of benzene
Volume benzene = mass / density
Volume benzene = 37.34 grams / 0.88g/mL
Volume benzene = 42.4 mL
We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat
The volume of benzene required is 42.5 mL of benzene.
The equation of the reaction is; 2C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ
If 2 mole of benzene produces -6278 kJ of heat
x moles of benzene produces 1.5 x 103 kJ
x = 2 mole × -1.5 x 10^3 kJ/ -6278 kJ
x = 0.48 moles of benzene
The mass of benzene required = number of moles of benzene x molar mass of benzene
Molar mass of benzene = 78 g/mol
Mass of benzene required = 0.48 moles of benzene × 78 g/mol
= 37.44 g
Density of benzene = 0.88 g/mL
But; density = mass/volume
Volume = mass/density
volume = 37.44 g/0.88 g/mL
volume = 42.5 mL of benzene
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