Respuesta :
Explanation:
Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.
Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{12 g}{60 g/mol}[/tex]
= 0.2 mol
Molarity of acetic acid is calculated as follows.
Density = [tex]\frac{mass}{volume}[/tex]
1 g/ml = [tex]\frac{100 g}{volume}[/tex]
volume = 100 ml
Hence, molarity = [tex]\frac{\text{no. of moles}}{volume}[/tex]
= [tex]\frac{0.2 mol}{0.1 L}[/tex]
= 2 mol/l
As reaction equation for the given reaction is as follows.
[tex]NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O[/tex]
So, moles of NaOH = moles of acetic acid
Let us suppose that moles of NaOH are "x".
[tex]x \times 1 M = 10 mL \times 2 M[/tex] (as 1 L = 1000 ml)
x = 20 L
Thus, we can conclude that volume of NaOH required is 20 ml.
