The force exerted on her is 1700 N
Explanation:
First of all, we start by calculating the acceleration of the car. Since its motion is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2 = 2as[/tex]
where
v = 0 is the final velocity of the car (which comes to a stop)
u = 14.0 m/s is the initial velocity
a is the acceleration
s = 3.0 m is the distance covered by the car during the collision
Solving for a,
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-14^2}{2(3)}=-32.7 m/s^2[/tex]
And the negative sign means it is a deceleration.
Now we can find the force exerted on the passenger during the collision, using Newton's second law:
[tex]F=ma[/tex]
where
F is the force
m = 52.0 kg is the mass of the passenger
[tex]a=32.7 m/s^2[/tex] is the acceleration (we ignore the sign since we are only interested in the magnitude of the force)
Substituting,
[tex]F=(52.0)(32.7)=1700 N[/tex]
Learn more about acceleration and forces:
brainly.com/question/11411375
brainly.com/question/1971321
brainly.com/question/2286502
brainly.com/question/2562700
#LearnwithBrainly
