Respuesta :

Answer:

DETAILS IN THE QUESTION INSUFFICIENT TO ANSWER

Explanation:

Assuming the liquid to be water ,

the density [tex]d_{w}[/tex] of water is : [tex]1000kgm^{-3}=1gcm^{-3}[/tex]

Buoyant force exerted by a liquid on an object with [tex]V_{imm}[/tex] of it's volume immersed is :

[tex]F_{B}=V_{imm}*d_{l}*g[/tex]

where ,

  • [tex]F_{B}[/tex] is the buoyant force
  • [tex]d_{l}[/tex] is the density of the liquid
  • [tex]g[/tex] is the acceleration due to gravity

Thus at equilibrium:

[tex]m_{brass}*g=V_{imm}*d_{l}*g\\m_{brass}=V_{imm}*d_{l}\\54=V_{imm}*1\\V_{imm}=54cm^{3}[/tex]

from these , we get the density of brass to be [tex]1gcm^{-3}[/tex]

which is not possible

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