Answer:
34 ft
Step-by-step explanation:
We are given that
BC=33 ft
AC=60.5 ft
[tex]\angle ACB=45-25=20^{\circ}[/tex]
We have to find the distance travel by baseball player to get to the ball.
Cosine law:[tex]c=\sqrt[a^2+b^2-2abcos\gamma}[/tex]
Substitute the values then we get
[tex]c=\sqrt{(33)^2+(60.5)^2-2(33)(60.5)cos 25^{\circ}}[/tex]
The distance traveled by base player to get to the ball [tex]=33.64\approx 34 ft[/tex]
Hence, the distance traveled by base player to get to the ball[tex]=34 ft[/tex]
