Answer:
     [tex] v_s =7.74\ m/s[/tex]
Explanation:
given,
Speed of sound = 343 m/s
frequency of horn = 260 Hz
the friend is approaching, the frequency is increased by the Doppler Effect. The frequency is 266 Hz
using formula
     [tex]f' = \dfrac{v}{v-v_s}f_0[/tex]
     [tex]266= \dfrac{343}{343 - v_s}(260)[/tex]
     [tex]1.023= \dfrac{343}{343 - v_s}[/tex]
     [tex]343 - v_s = 335.26[/tex]
     [tex] v_s =7.74\ m/s[/tex]
the speed of friends approaching is equal to [tex] v_s =7.74\ m/s[/tex]