An angle's initial ray points in the 3-o'clock direction and its terminal ray rotates CCW. Let θ represent the angle's varying measure (in radians).

If θ=0.5θ=0.5 what is the slope of the terminal ray?
If θ=1.78θ=1.78, what is the slope of the terminal ray?

Write an expression (in terms of θθ) that represents the varying slope of the terminal ray.

Respuesta :

Answer:

0.546 , -4.71

Step-by-step explanation:

Given:

An angle's initial ray points in the 3-o'clock direction and its terminal ray rotates counter -clock wise.

Here, Slope = tan\theta

If θ = 0.5

Then, Slope = tan(θ) = tan(0.5) = 0.546

If θ = 1.78

Then, Slope = tan(θ) = tan(1.78) = - 4.71

The expression (in terms of θ) that represents the varying slope of the terminal ray.

Slope = m = tanθ, where θ is the varying angle

A) The slope of the terminal ray when θ = 0.5 radians is; 0.5463

B) The slope of the terminal ray when θ = 1.78 radians is; -4.71

C) The expression that will represent the varying slope of the terminal ray is;

tan (Δy/Δx)

We are given that θ represents the angle's varying measure (in radians).

Now, in mathematics, slope is simply the tangent of an angle. Thus;

A) At θ = 0.5 radians ,

Slope of terminal ray = tan θ

Slope = tan 0.5

Using radians calculator, tan 0.5 = 0.5463

Thus, slope = 0.5463

B) At θ = 1.78

Slope of terminal ray = tan θ

Slope = tan 1.78

Using radians calculator, tan 1.78 = -4.71

Thus, slope = -4.71

C) The expression that will represent the varying slope of the terminal ray is;

tan (Δy/Δx)

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