Answer:
6.25 m/s
196 kg/s
Explanation:
The areas of the pipe from big to small:
[tex]A = \pi R^2 = \pi*0.25^2 = 0.196 m^2[/tex]
[tex]a = \pi r^2 = \pi*0.1^2=0.0314m^2[/tex]
As the product of speed and cross-section area is constant, the speed in the smaller pipe would be
[tex]AV = av[/tex]
[tex]v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s[/tex]
The mass flow rate would be:
[tex]\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s[/tex]
