Answer:0.122 N/m
Explanation:
Given
Maximum Amplitude can be obtained when tapped after every second
i.e. Time Period [tex]T=1 s[/tex]
mass of spider [tex]m=3.1 gm[/tex]
and we know
[tex]T\cdot \omega =2\pi [/tex]
where [tex]\omega [/tex]=natural frequency of oscillation
T=time Period
[tex]\omega [/tex] is also given by [tex]\omega =\sqrt{\frac{k}{m}}[/tex]
[tex]1\cdot \sqrt{\frac{k}{m}}=2\pi [/tex]
[tex]1\cdot \sqrt{\frac{k}{3.1\times 10^{-3}}}=2\pi [/tex]
[tex]k=(2\pi )^2\times 3.1\times 10^{-3}[/tex]
[tex]k=0.122 N/m[/tex]
