Answer:
4.924 units.
Step-by-step explanation:
See the attached diagram.
If P is the midpoint of AB and Q is the midpoint of AC, then PQ is parallel to BC and the length of PQ will be half of BC.
Now, the coordinates of B are (1,1) and that of C is (10,-3).
Therefore the length of BC is [tex]\sqrt{(10 - 1)^{2} + (- 3 - 1)^{2}} = 9.848[/tex] units (Approximate)
Therefore, the length of PQ = 0.5 × 9.848 = 4.924 units. (Answer)
We know that the distance between two given points ([tex]x_{1},y_{1}[/tex]), and ([tex]x_{2},y_{2}[/tex]) is given by the formula
[tex]\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}[/tex]
