Answer:
L=0.0074 mm
Explanation:
Given that
d= 6.5 micron meter
d= 6.5 x 10⁻³ mm
Yield strength ,Sy = 73 MPa
Bond strength ,σ = 32 MPa
The fiber length given as
[tex]L=\dfrac{S_y \times d}{2 \times \sigma }[/tex]
By putting the values
[tex]L=\dfrac{S_y \times d}{2 \times \sigma }[/tex]
[tex]L=\dfrac{73 \times 6.5\times 10^{-3}}{2\times 32 }\ mm[/tex]
L=0.0074 mm
Therefore the minimum fiber length is 0.0074 mm.
