Respuesta :
Answer:
2.04 is the pOH of a 0.0092 M CsOH solution.
Explanation:
Molarity of cesium hydroxde = [CsOH]= 0.0092
[tex]CsOH(aq)\rightarrow Cs^+(aq)+OH^-(aq)[/tex]
1 mole of cesium hydroxide gives 1 mole of cesium ion and 1 mole of hydroxide ion.
Then 0.0092 M cesium hydroxide will give :
[tex][OH^-]=1\times [CsOH]=1\times 0.0092 M=0.0092M [/tex]
The pOH of the solution is the negative logarithm of concentration of hydroxide ions in a solution.
[tex]pOH=-\log [OH^-][/tex]
[tex]pOH=-\log [0.0092 M]=2.0362\approx 2.04 [/tex]
2.04 is the pOH of a 0.0092 M CsOH solution.
