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wo balls have the same mass of 5.00 kg. Suppose that these two balls are attached to a rigid massless rod of length 2L, where L = 0.550 m. One is attached at one end of the rod and the other at the middle of the rod. If the rod is held by the open end and rotates in a circular motion with angular speed of 45.6 revolutions per second,

Respuesta :

Answer:

  [tex]T_1 =677224.40\ N[/tex]

Explanation:

given,

mass of the both ball = 5 Kg

length of rod = 2 L            

where L = 0.55 m            

angular speed = 45.6 rev/s

ω = 45.6 x 2 π                      

ω = 286.51 rad/s                

v₁ = r₁ ω₁                        

v₁ =0.55 x 286.51 = 157.58 m/s

v₂ = r₂ ω₂                                

v₂ = 1.10 x 286.51 = 315.161 m/s

finding tension on the first half of the rod

r₁ = 0.55  r₂ = 2 x r₁ = 1.10

  [tex]T_1 = m (\dfrac{v_1^2}{r_1}+\dfrac{v_2^2}{r_2})[/tex]

  [tex]T_1 = 5 (\dfrac{157.58^2}{0.55_1}+\dfrac{315.161^2}{1.1})[/tex]

  [tex]T_1 =677224.40\ N[/tex]

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