Answer:
1.5 g/cm^3
Explanation:
In the question i am assuming that wooden block of weight W floats with exactly one-half of its volume below the waterline.
Let ρ_{liquid} be the density of the unknown liquid , V= volume submerged
g= acceleration due to gravity
then
weight of block = [tex]\rho_{water}\times V\times g/2[/tex]
when the block is in water
Also,
weight of block = [tex]\rho_{liquid}\times V\times g/3[/tex]
dividing eq 1 by eq 2 we get
[tex]\rho_{liquid} = 3/2 \rho_{water}[/tex]
⇒[tex]\rho_{liquid} = 3/2[/tex]
