Answer:
The maximum kinetic energy of the ejected electron=[tex]3.53\times 10^{-10} J[/tex]
Explanation:
We are given that
Frequency of light source=[tex]5.32\times 10^{23}[/tex] Hz
Work function of arsenic=[tex]7.67\times 10[/tex] eV
We have to find the maximum kinetic energy of ejected electron.
We know that the maximum kinetic energy of ejected electron
[tex]K.E=h\nu-w_o[/tex]
Where h=Plank's constant=[tex]6.63\times 10^{-34} J.s[/tex]
[tex]\nu[/tex] =Frequency of light source
[tex]w_o[/tex]=Work function
Substitute the values in the given formula
Then, the maximum kinetic energy of ejected electron
[tex]K.E=6.63\times 10^{-34}\times 5.32\times 10^{23}-7.67\times 10\times 1.6\times 10^{-19}[/tex]
Because 1 e V=[tex]1.6\times 10^{-19} J[/tex]
[tex]K.E=35.2716\times 10^{-11}-12.272\times 10^{-18}[/tex]
[tex]K.E=3.53\times 10^{-10}[/tex] J
Hence, the maximum kinetic energy of the ejected electron=[tex]3.53\times 10^{-10} J[/tex]
