Respuesta :
Answer:
The moment of inertia of yard stick about pivot point is 0.05121 kg.m².
Explanation:
Given that,
Mass of stick = 735 g
Distance = 50 cm
We need to calculate the moment of inertia of yard stick about pivot point
Using formula of moment of inertia
[tex]I=\dfrac{ml^2}{12}+m(\dfrac{1}{2}-d)^2[/tex]
Where, m = mass of stick
l = distance
Put the value into the formula
[tex]I=\dfrac{0.735\times(0.9144)^2}{12}+0.735\times(\dfrac{1}{2}-50\times10^{-2})^2[/tex]
[tex]I=0.05121\ kg.m^2[/tex]
Hence, The moment of inertia of yard stick about pivot point is 0.05121 kg.m².
The moment of inertia of this yard stick is equal to 0.0512 [tex]kgm^2[/tex]
Given the following data:
Mass of uniform yard stick = 735 g to kg = 0.735 kg.
Distance = 50 cm to m = 0.5 m.
Note: The length of the meter stick is 0.9144 m.
How to calculate the moment of inertia.
Mathematically, the moment of inertia of a yard stick is given by this formula:
[tex]I=\frac{ML^2}{12} +M(\frac{L}{2} -d)^2[/tex]
Where:
- I is the moment of inertia.
- L is the length.
- M is the mass.
- d is the distance.
Substituting the parameters into the formula, we have;
[tex]I=\frac{0.735 \times 0.9144^2}{12} +0.735(\frac{0.9144}{2} -0.50)^2\\\\I=0.0512\;kgm^2[/tex]
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