Respuesta :
Answer:
The concentration of acetic acid in the vinegar is 7,324 (%V/V)
Explanation:
The titration equation of acetic acid with NaOH is:
NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O
The moles required were:
1,024M×0,02500L = 0,02560 moles NaOH. These moles are equivalent (By the titration equation) to moles of CH₃COOH. As molar mass of CH₃COOH is 60,052g/mol, the mass in these moles of CH₃COOH is:
0,02560 moles CH₃COOH×[tex]\frac{60,052g}{1mol}[/tex]= 1,537g of CH₃COOH
As density is 1,01g/mL:
1,537g CH₃COOH×[tex]\frac{1mL}{1,01g}[/tex]= 1,522mL of CH₃COOH
As volume of vinegar in the sample is 20,78mL, the concentration of acetic acid in the vinegar is:
[tex]\frac{1,522mLCH_{3}COOH}{20,78mL}[/tex]×100= 7,324 (%V/V)
I hope it helps!
Considering the definition, molarity, density and volume percentage, the concentration of acetic acid in the vinegar is 7.32% (v/v).
The balanced reaction is:
NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O
Molarity is the number of moles of solute that are dissolved in a given volume. Molarity is determined by:
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case you know for NaOH:
- Molarity= 1.024 M
- number of moles of solute= ?
- Volume= 25 mL= 0.025 L
So, the moles required are calculated as:
[tex]1.024 M=\frac{number of moles of solute}{0.025 L}[/tex]
Solving:
1.024 M× 0.025 L= number of moles of solute
0.0256 moles= number of moles of solute
By observing the balanced reaction, you can see that, since the ratio of CH₃COOH to NaOH is 1: 1, these moles are equivalent to the number of moles of CH₃COOH.
On the other hand, since the molar mass of CH₃COOH is 60.052 g/mol, this is the mass that contains one mole of the compound, the mass in 0.0256 moles of CH₃COOH is:
[tex]0.0256 molesx\frac{60.052 grams}{1 mole} =[/tex] 1.537 grams
Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
In this case, being the density 1.01 [tex]\frac{g}{mL}[/tex], the volume can be calculated as:
[tex]1.01 \frac{g}{mL} =\frac{1.537 grams}{volume}[/tex]
Solving:
1.01 [tex]\frac{g}{mL}[/tex]× volume= 1.537 grams
[tex]volume=\frac{1.537 grams}{1.01 \frac{g}{mL} }[/tex]
volume= 1.522 mL of CH₃COOH
Volume Percentage (%v/v) is a measure of concentration that indicates the volume of solute per 100 volume units of the solution. In other words, the volume percent of a component in the solution is defined as the ratio of the volume of the component to the volume of the solution, expressed as a percentage.
The volume percentage of a solution is determined by the following expression:
[tex]volume percentage=\frac{volume of solute}{volume of solution}x100[/tex]
Then, as volume of vinegar in the sample is 20,78mL, the concentration of acetic acid in the vinegar is:
[tex]volume percentage=\frac{1.522 mL}{20.78 mL}x100[/tex]
Solving:
volume percentage= 7.32%
Finally, the concentration of acetic acid in the vinegar is 7.32% (v/v).
Learn more about:
- molarity with this example:
- brainly.com/question/15406534?referrer=searchResults
- density:
- brainly.com/question/952755?referrer=searchResults
- brainly.com/question/1462554?referrer=searchResults
- volume percentage
- brainly.com/question/1713808
