On a certain hot​ summer's day, 643 people used the public swimming pool. The daily prices are $1.50 for children and $2.00 for adults. The receipts for admission totaled
$1161.50. How many children and how many adults swam at the public pool that​ day?

Respuesta :

249 children and 394 adults swam at the public pool.

Step-by-step explanation:

Number of people swam at pool = 643

Receipts = $1161.50

Cost for one child = $1.50

Cost for one adult = $2.00

Let,

x be the number of children

y be the number of adults

According to given statement;

x+y=643    Eqn 1

1.50x+2.00y = 1161.50   Eqn 2

Multiplying Eqn 1 by 2

[tex]2(x+y=643)\\2x+2y=1286\ \ \ Eqn\ 3\\[/tex]

Subtracting Eqn 2 from Eqn 3

[tex](2x+2y)-(1.50x+2.00y)=1286-1161.50\\2x+2y-1.50x-2.00y=124.50\\0.5x=124.50[/tex]

Dividing both sides by 0.5

[tex]\frac{0.5x}{0.5}=\frac{124.50}{0.5}\\x=249[/tex]

Putting x=249 in Eqn 1

[tex]249+y=643\\y=643-249\\y=394[/tex]

249 children and 394 adults swam at the public pool.

Keywords: linear equation, subtraction

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