Respuesta :
a) Na is oxidised Br is reduced
b) H is oxidised Cl is reduced
c) Li is oxidised F is reduced
d)S is oxidised Cl is reduced
e) N is oxidised O is reduced
f) Mg is oxidised and N is reduced
Remember: Oxidation= loss and Reduction= gains
b) H is oxidised Cl is reduced
c) Li is oxidised F is reduced
d)S is oxidised Cl is reduced
e) N is oxidised O is reduced
f) Mg is oxidised and N is reduced
Remember: Oxidation= loss and Reduction= gains
Answer :
Oxidation-reduction reaction : It is a type of reaction in which oxidation and reduction reaction occur simultaneously.
Oxidation reaction : It is the reaction in which a substance looses its electrons. In the oxidation reaction, the oxidation state of an element increases.
Reduction reaction : It is the reaction in which a substance gains electrons. In the reduction reaction, the oxidation state of an element decreases.
(a) The balanced chemical reactions is,
[tex]2Na(s)+Br_2(l)\rightarrow 2NaBr(s)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]Na\rightarrow Na^{1+}+1e^-[/tex]
Reduction : [tex]Br_2+2e^-\rightarrow 2Br^{1-}[/tex]
From this we conclude that, 'Na' is oxidized and [tex]'Br_2'[/tex] is reduced in this reaction. The reducing agent is, 'Na' and oxidizing agent is, [tex]'Br_2'[/tex].
(b) The balanced chemical reactions is,
[tex]H_2(g)+Cl_2(g)\rightarrow 2HCl(g)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]H_2\rightarrow H^{1+}+1e^-[/tex]
Reduction : [tex]Cl_2+2e^-\rightarrow 2Cl^{1-}[/tex]
From this we conclude that, [tex]'H_2'[/tex] is oxidized and [tex]'Cl_2'[/tex] is reduced in this reaction. The reducing agent is, [tex]'H_2'[/tex] and oxidizing agent is, [tex]'Cl_2'[/tex].
(c) The balanced chemical reactions is,
[tex]2Li(s)+F_2(g)\rightarrow 2LiF(s)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]Li\rightarrow Li^{1+}+1e^-[/tex]
Reduction : [tex]F_2+2e^-\rightarrow 2F^{1-}[/tex]
From this we conclude that, 'Li' is oxidized and [tex]'F_2'[/tex] is reduced in this reaction. The reducing agent is, 'Li' and oxidizing agent is, [tex]'F_2'[/tex].
(d) The balanced chemical reactions is,
[tex]S(s)+Cl_2(g)\rightarrow SCl_2(g)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]S\rightarrow S^{2+}+2e^-[/tex]
Reduction : [tex]Cl_2+2e^-\rightarrow 2Cl^{1-}[/tex]
From this we conclude that, 'S' is oxidized and [tex]'Cl_2'[/tex] is reduced in this reaction. The reducing agent is, 'S' and oxidizing agent is, [tex]'Cl_2'[/tex].
(e) The balanced chemical reactions is,
[tex]N_2(g)+2O_2(g)\rightarrow 2NO_2(g)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]N_2\rightarrow N^{4+}+4e^-[/tex]
Reduction : [tex]O_2+4e^-\rightarrow 2O^{2-}[/tex]
From this we conclude that, [tex]'N_2'[/tex] is oxidized and [tex]'O_2'[/tex] is reduced in this reaction. The reducing agent is, [tex]'N_2'[/tex] and oxidizing agent is, [tex]'O_2'[/tex].
(f) The balanced chemical reactions is,
[tex]Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)[/tex]
Half reactions of oxidation and reduction are :
Oxidation : [tex]Mg\rightarrow Mg^{2+}+2e^-[/tex]
Reduction : [tex]Cu^{2+}+2e^-\rightarrow Cu[/tex]
From this we conclude that, [tex]'Mg'[/tex] is oxidized and [tex]'Cu'[/tex] is reduced in this reaction. The reducing agent is, 'Mg' and oxidizing agent is, 'Cu'.
