Answer:
The acceleration would be a=1 m/s^2. Let's explain why.
Explanation:
Let's say the block is □
20N→□ Block is pushed with a constant horizontal force of 20N
□←10N It is known that frictional force is the opposite way of the movement
So it is safe to say that there is 10 N force trying to stop the block.
In this case our net force is [tex]F_{net} = 20-10=10N[/tex]
According to Newton's second motion law
[tex]F=m.a[/tex] (m=mass, F=force, a=acceleration
[tex]F_{net} =10=10.a[/tex] → [tex]a=1\frac{m^{2} }{s}[/tex]
As an extra information the block also applies gravitational m.g force down but since there is no other force applies in the vertical way, ground compansate the force.
