Respuesta :

risobel523

Answer:

Kinetic energy = (1/2)*m*v^2.  So we have (1/2)*(145 g)*(37 m/s)^2 = (1/2)*(2.5 g)*(v^2).

Solve for v = 281.78 m/s {about 630 miles per hour}

Explanation:

asifejaz20

Answer:

Velocity of ping-pong ball = V1 = 289.4 m/s

Explanation:

Mass of ping-pong ball = m1 = 2.5 g = 0.0025 kg  

Mass of baseball = m2 = 145 g = 0.145 kg  

Velocity of baseball = V2 = 38 m/s  

Velocity of ping-pong ball = V1 = ?

Kinetic energy of baseball = K.E2 = (1/2)(m2)(V2)^2

                                                        = (1/2)(0.145)(38)^2

                                                        = 104.69 J

It is given that:

Kinetic of ping-pong ball = kinetic energy of baseball  

                                 K.E1 = K.E2  

                 (1/2)(m1)(V1)^2 = 104.69  

                                    V1 = √(104.69)(2)/0.0025

                                    V1 = 289.4 m/s

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