Answer:
9 dBm or 7.94 mW
Explanation:
As per the question:
Signal generated by the transmitter, [tex]x_{T}[/tex] = 15 dBm
Loss by the antenna, L = 2 dB
No. of connectors, n = 2
Loss by each connector, l = 2 dB
Now,
The signal level at the input of the antenna:
[tex]P = x_{T} - L - nl = 15 - 2 - 2\times 2 = 9\ dBm[/tex]
Now, the signal level at the input in milliwatt:
[tex]P = \frac{10^{\frac{P(in\ dBm)}{10}}}{1000}[/tex]
[tex]P = \frac{10^{\frac{9}{10}}}{1000} = 7.94\ mW[/tex]
