Zinc metal reacts with hydrochloric acid according to this balanced equation. Zn(s) 2HCl(aq)→ZnCl2(aq) H2(g) When 0.114 g of Zn(s) is combined with enough HCl to make 52.4 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.0 ∘C to 23.9 ∘C.

Respuesta :

Answer: The enthalpy change of the reaction is 239.2 kJ/mol

Explanation:

  • To calculate the mass of solution, we use the equation:

[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]

Density of solution = 1.0 g/mL

Volume of solution = 52.4 mL

Putting values in above equation, we get:

[tex]1.0g/mL=\frac{\text{Mass of solution}}{52.4mL}\\\\\text{Mass of solution}=(1.0g/mL\times 52.4mL)=52.4g[/tex]

  • To calculate the heat absorbed we use the equation:

[tex]q=mc\Delta T[/tex]

where,

q = heat absorbed = ?

m = mass of solution = 52.4 g

c = specific heat capacity of solution = 4.18 J/g.°C

[tex]\Delta T[/tex] = change in temperature = [tex](23.9-22.0)^oC=1.9^oC[/tex]

Putting values in above equation, we get:

[tex]q=52.4g\times 4.18J/g.^oC\times 1.9^oC\\\\q=416.2J[/tex]

Heat absorbed by the solution = heat released by the reaction

  • To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of zinc = 0.114 g

Molar mass of zinc = 65.4 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of zinc}=\frac{0.114g}{65.4g/mol}=0.00174mol[/tex]

  • Calculating the amount of heat released per mole of zinc, we get:

[tex]\Delta H_{rxn}=\frac{\text{Heat released in the reaction}}{\text{Moles of zinc}}\\\\\Delta H_{rxn}=\frac{-416.2}{0.00174}=239195.4J/mol=239.2kJ/mol[/tex]

Conversion factor:  1 kJ = 1000 J

Hence, the enthalpy change of the reaction is 239.2 kJ/mol

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