Respuesta :
Answer:
The magnitude of the acceleration of the baseball is 8000 m/s² in east direction.
Explanation:
Given that,
Mass of baseball = 0.14 kg
Initial velocity of the ball = 45 m/s
Final velocity = 35 m/s
Suppose The bat and ball are in contact for [tex]1.0\times10^{-2}\ sec[/tex]
We determine the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat
We need to calculate the magnitude and direction of average acceleration of the baseball
Using force of impulse
Impulse :
Impulse is equal to the product of the force and time.
[tex]J=F\times t[/tex]...(I)
Impulse is equal to the change in momentum.
[tex]J=m\delta v[/tex]...(II)
Using equation (I) and (II)
[tex]F\times t=m\delta v[/tex]
[tex]ma\times t=m\times\delta v[/tex]
Put the value into the formula
[tex]a=\dfrac{(35i-(-45i))}{10^{-2}}[/tex]
[tex]a=\dfrac{80i}{1.0\times10^{-2}}[/tex]
[tex]a=8000i\ m/s^2[/tex]
Hence, The magnitude of the acceleration of the baseball is 8000 m/s² in east direction.
