Answer:
(a) 172.185 N
(b) [tex]53^{\circ}[/tex]
Solution:
As per the question:
Mass of the child, m = 22.0 kg
Angle, [tex]\theta = 37.0^{\circ}[/tex]
Now,
(a) The magnitude of the normal force exerted by the slide on the child:
[tex]F_{N} = mgcos\theta [/tex]
[tex]F_{N} = 22\times 9.8cos37^{\circ} = 172.185\ N[/tex]
Now,
(b) The angle from the horizontal at which the force is directed is:
[tex]90^{\circ} - 37^{\circ} = 53^{\circ}[/tex]
