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In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above the launch point that is four times greater than that of ball b. The launch speed of ball a is _______ times greater than that of ball b.

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Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

[tex]Ymax = \frac{Vo^2}{2g}[/tex]

Since we are told that Ya = 4Yb:

[tex]Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}[/tex]

Simplifying the equation:

[tex]Va^2 = 4*Vb^2[/tex]

[tex]Va = 2*Vb[/tex]

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