Answer:
The sum of the areas of the two shaded sectors is [tex]36\pi\ units^{2}[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a circle is equal to
[tex]A=\pi r^{2}[/tex]
where
r is the radius of the circle
in this problem we have
[tex]r=9\ units[/tex]
substitute
[tex]A=\pi (9)^{2}=81 \pi\ units^{2}[/tex]
Remember that
[tex]360\°[/tex] subtends the complete circle of area equal to [tex]81 \pi\ units^{2}[/tex]
so
By proportion
Find the area of the two shaded sectors
[tex]\frac{81\pi }{360}=\frac{x}{2*80}\\ \\x=160*81\pi/360\\ \\x=36\pi\ units^{2}[/tex]
