An astronaut and his gear are at rest with respect to his shuttlecraft . The astronaut and the shuttlecraft are initially separated by a distance of m. If the astronaut moves farther away from the shuttlecraft to a distance of m, what is the change in gravitational potential energy for the astronaut–shuttlecraft system?

Respuesta :

Answer:

[tex]\Delta F = (Gm_Am_S)[-\frac{1}{r_2}+\frac{1}{r_1}][/tex]

Explanation:

We need the Gravitational Potential Energy equation to give solution to this problem.

This equation is,

[tex]F=\frac{-Gm_1m_2}{r}[/tex]

Where r is the distance between the corps.

The rate from this gravitational potential energy is given by,

[tex]\Delta F = \frac{-Gm_Am_S}{r_2} - (\frac{Gm_Am_S}{r_1})[/tex]

[tex]\Delta F = (Gm_Am_S)[-\frac{1}{r_2}+\frac{1}{r_1}][/tex]

You need only replace the values to find the Energy.

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