The number $n$ is randomly selected from the set $\{1, 2,\ldots, 10\}$, with each number being equally likely. What is the probability that $2n - 4 > n$?

Respuesta :

Answer:

The probability would be 3/5

Step-by-step explanation:

Here,

n ∈ { 1, 2, ..........., 10}

Also, the given inequality,

2n - 4 > n

By using a > b ⇒ a ± c > b ± c ∀ a, b, c ∈ R,

2n - 4 - n > 0

n - 4 > 0

n > 4,

Thus, the numbers which are following the given inequality are,

{5, 6, 7, 8, 9, 10}

Now,

[tex]\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}[/tex]

Since, numbers which are more than 4 = 6,

Total numbers = 10,

Hence, the probability that 2n - 4 > n

[tex]=\frac{6}{10}=\frac{3}{5}[/tex]

Answer:

The probability is 3/8

Step-by-step explanation:

Of the eight possible outcomes, there are three successful ones: HHH, HHT, and THH, so, the probability is 3/8

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