Answer:
Wfr=-496.4 J
Explanation:
The total work of the motion is describe
x=5.0m
v=9.0 m/s
m=58.4kg
[tex]W_{total}=W_{g}+W_{fr}[/tex]
[tex]W_{total}=\frac{1}{2}*m*(v_{f})^{2}\\W_{g}=m*g*x[/tex]
The Work of the friction can be find without know the coefficient however knowing the total work and the work done by the gravity down a ramp can find the work of the friction
[tex]W_{fr}=W_{total}-W_{g}\\W_{fr}=\frac{1}{2}*m*(v_{f})^{2}-m*g*x[/tex]
[tex]W_{fr}=\frac{1}{2}*58.4kg*(9\frac{m}{s})^{2}-58.4kg*9.8\frac{m}{s^{2}}*(0m-5m)\\W_{fr}=-496.4 J[/tex]
