Respuesta :
Answer :
(a) Molecular structure = Square planar
Bond angle = [tex]90^o[/tex]
(b) Molecular structure = Bent or Angular
Bond angle = [tex]104.5^o[/tex]
Explanation :
To determine the hybridization of the following molecules by using formula as :
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
(a) The given molecule is, [tex]XeCl_4[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [8+4]=6[/tex]
Bond pair electrons = 4
Lone pair electrons = 6 - 4 = 2
The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.
But as there are four atoms around the central xenon atom, the fifth and sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square planar and the bond angle will be [tex]90^o[/tex].
(b) The given molecule is, [tex]SCl_2[/tex]
[tex]\text{Number of electrons}=\frac{1}{2}\times [6+2]=4[/tex]
Bond pair electrons = 2
Lone pair electrons = 4 - 2 = 2
The number of electrons are 6 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
But as there are 2 atoms around the central sulfur atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular and the bond angle will be [tex]104.5^o[/tex].
