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A stone dropped into a still pond sends out a circular ripple whose radius increases at a constant rate of 2 ft/s. (a) How rapidly is the area enclosed by the ripple increasing when the radius is 5 feet?

Respuesta :

Answer:

62.83185 ft/s

Explanation:

r = Radius of circle

t = Time

[tex]\frac{dr}{dt}[/tex] = 2 ft/s

A = Area of circle

[tex]A=\pi r^2[/tex]

Differentiating with respect to time

[tex]\frac{dA}{dt}=2\pi r\frac{dr}{dt}[/tex]

when r = 5 feet

[tex]\frac{dA}{dt}=2\pi 5\times 2\\\Rightarrow \frac{dA}{dt}=62.83185\ ft/s[/tex]

The area is increasing at a rate of 62.83185 ft/s

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