A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another, one in the x direction another in the y direction. Both of these pieces fly away with a speed of V = 31 m/s. The third piece has three times the mass of the other two pieces.

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Answer

given,

watermelon blown into three pieces

two pieces of mass m

both pieces speed = v = 31 m/s

mass of third piece = 3 m

using conservation of mass

[tex]0 = m V \hat{i} + m V \hat{j} + (3\ m)V_3[/tex]

[tex]V_3 = \dfrac{V}{3}(-\hat{i}-\hat{j})[/tex]

[tex]V_3 = \dfrac{V}{3}\sqrt{1^2+1^2}[/tex]

[tex]V_3 = \dfrac{V}{3}\sqrt{2}[/tex]

velocity of third component

[tex]V_3 = \dfrac{31}{3}\sqrt{2}[/tex]

[tex]V_3 = 14.61\ m/s[/tex]

angle

[tex]\theta = tan^{-1}(\dfrac{-1}{-1})[/tex]

[tex]\theta = tan^{-1}(1)[/tex]

[tex]\theta = 45^0[/tex]

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