Answer
given,
watermelon blown into three pieces
two pieces of mass m
both pieces speed = v = 31 m/s
mass of third piece = 3 m
using conservation of mass
[tex]0 = m V \hat{i} + m V \hat{j} + (3\ m)V_3[/tex]
[tex]V_3 = \dfrac{V}{3}(-\hat{i}-\hat{j})[/tex]
[tex]V_3 = \dfrac{V}{3}\sqrt{1^2+1^2}[/tex]
[tex]V_3 = \dfrac{V}{3}\sqrt{2}[/tex]
velocity of third component
[tex]V_3 = \dfrac{31}{3}\sqrt{2}[/tex]
[tex]V_3 = 14.61\ m/s[/tex]
angle
[tex]\theta = tan^{-1}(\dfrac{-1}{-1})[/tex]
[tex]\theta = tan^{-1}(1)[/tex]
[tex]\theta = 45^0[/tex]