In the reaction 2HgO(s) --> 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 minutes), 0.02 L of O2 is present. After 10 minutes the volume of O2 is 0.36 L. What is the rate of reaction? Question 4 options:

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