Answer:
The acceleration of the both masses is 0.0244 m/s².
Explanation:
Given that,
Mass of one block = 602.0 g
Mass of other block = 717.0 g
Radius = 1.70 cm
Height = 60.6 cm
Time = 7.00 s
Suppose we find the magnitude of the acceleration of the 602.0-g block
We need to calculate the acceleration
Using equation of motion
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Where, s = distance
t = time
a = acceleration
Put the value into the formula
[tex]60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2[/tex]
[tex]a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}[/tex]
[tex]a=0.0244\ m/s^2[/tex]
Hence, The acceleration of the both masses is 0.0244 m/s².
