Answer:
[tex]E=-8.72\times 10^{-18}\ Joules[/tex]
Explanation:
The expression for Bohr energy of the hydrogen-like species is:
[tex]E_n=-Z^2\times \frac{2.179\times 10^{-18}}{n^2}\ Joules[/tex]
Where, Z is the atomic number of the element
For, [tex]He^{2+}[/tex], Z = 2
For lowest energy, n = 1
Thus, Applying the values as:-
[tex]E=-2^2\times \frac{2.179\times 10^{-18}}{1^2}\ Joules[/tex]
[tex]E=-8.72\times 10^{-18}\ Joules[/tex]
