In the given diagram, ABC is a right triangle with DGCB. Segment AB is divided into four equal parts.
A(-3,-1)
C-3,-3)
B(6,-3)
The coordinates of point Fare
), and the coordinates of point G are
.

Respuesta :

The coordinates of point F are (3.75, -2.5), and the coordinates of point G are (-0.75 , -3)

How to determine the coordinates of F and G?

The coordinates are given as:

A(-3,-1)

C-3,-3)

B(6,-3)

The diagram that completes the question is added as an attachment.

From the attached diagram, we have:

  • Point G ⇒ m : n = 1 : 3 between C and B
  • Point F ⇒ m : n = 3 : 1 between A and B

The vertices of the points are calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

So, we have:

[tex]G = \frac{1}{1 + 3} * (1 * 6 + 3 * -3 , 1 * -3 + 3 * -3)[/tex]

Evaluate

G = (-0.75 , -3)

Also, we have:

[tex]F = \frac{1}{3 + 1} * (3 * 6 + 1 * -3 , 3 * -3 + 1 * -1)[/tex]

Evaluate

F = (3.75, -2.5)

Hence, the coordinates of point F are (3.75, -2.5), and the coordinates of point G are (-0.75 , -3)

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