Answer:v=39.051 m/s
Explanation:
Given
Two cars having same mass, let say m
One is traveling east 50 km/h and one is traveling 60 km/h south
after collision they stick together and move with common velocity v at angle of [tex]\theta [/tex]
conserving Momentum in east i.e horizontal direction
[tex]m\cdot 50=(m+m)v\cos \theta [/tex]---1
conserving momentum in south direction i.e. in vertical direction
[tex]m\cdot 60=(m+m)v\sin \theta [/tex]---2
Divide 1 &2 Â we get
[tex]\frac{50}{60}=\frac{\cos \theta }{\sin \theta }[/tex]
[tex]\tan \theta =\frac{6}{5}[/tex]
[tex]\theta =50.19^{\circ}[/tex] w.r.t east clockwise
Put value of [tex]\theta [/tex] is equation 1
[tex]m\cdot 50=2m\cdot v\cos 50.19[/tex]
[tex]v=39.05 m/s[/tex]
