The student is wrong because he just calculated the perimeter as:
[tex]P=L+W[/tex]
And forgot to multiply both W and L by 2.
For any rectangle, the perimeter can be found as:
[tex]P=2W+2L \\ \\ \\ Where: \\ \\ W:Width \\ \\ L:Length \\ \\ P:Perimeter[/tex]
In this case, a student has a rectangle whose dimensions are:
[tex]L=2x-1 \\ \\ W:3x[/tex]
So the perimeter should be calculated as follows:
[tex]P=2(3x)+2(2x-1) \\ \\ Simplifying: \\ \\ P=6x+4x-2 \\ \\ \boxed{P=10x-2}[/tex]
The student is wrong because he just calculated the perimeter as:
[tex]P=L+W[/tex]
And forgot to multiply both W and L by 2.
Quadrilaterals: https://brainly.com/question/11131466
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