[tex]\boxed{A=12x^2-31x+7}[/tex]
Remember that for any rectangle whose dimensions are:
[tex]L:\ Length \\ \\ W: \ Width[/tex]
The area (A) can be calculated as:
[tex]A=L\times W[/tex]
In this case, the dimensions are:
[tex]L=3x-7 \\ \\ W=4x-1[/tex]
Therefore:
[tex]A=(3x-7)(4x-1) \\ \\ By \ Distributive \ Property: \\ \\ A=(3x)(4x)-3x-28x+7 \\ \\ A=12x^2-3x-28x+7 \\ \\ \boxed{A=12x^2-31x+7}[/tex]
Perimeter of a rectangle: https://brainly.com/question/13748917#
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