Answer:
A
Step-by-step explanation:
Before we can add the 2 fractions we require them to have a common denominator.
Multiply the numerator/ denominator of the first fraction by x
Multiply the numerator/ denominator of the second fraction by (x + 3)
= [tex]\frac{3x(x)}{x(x+3)}[/tex] + [tex]\frac{(x-2)(x+3)}{x(x+3)}[/tex]
Now simplify the numerator, leaving the denominator
= [tex]\frac{3x^2+x^2+x-6}{x(x+3)}[/tex]
= [tex]\frac{4x^2+x-6}{x(x+3)}[/tex] → A
