A 1.9 cm3 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.7 atm . The bubble rises slowly enough that the air inside remains at the same constant temperature as the water.

Respuesta :

Answer:

The volume of bubble is 5.13 cm³.

Explanation:

Given that,

Volume of air bubble = 1.9 cm³

Gauge pressure = 1.7 atm

Suppose we find the volume of the bubble as it reaches the surface

We need to calculate the pressure at bottom

Pressure at bottom=gauge pressure+atmospheric pressure

[tex]P=1.7+1.0=2.7\ atm[/tex]

We need to calculate the volume of bubble

Using Boyle's law

[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]

Put the value into the formula

[tex]2.7\times1.9=1.0\times V_{2}[/tex]

[tex]V_{2}=\dfrac{2.7\times1.9}{1.0}[/tex]

[tex]V_{2}=5.13\ cm^{3}[/tex]

Hence, The volume of bubble is 5.13 cm³.

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