[tex]Vertex: \ (2,3)[/tex]
Explanation:
The vertex form of the equation of a parabola is given by the following form:
[tex]f(x)=a(x-h)^2+k \\ \\ Where: \\ \\ a:Leading \ Coefficient \\ \\ (h,k):Vertex \ of \ the \ parabola[/tex]
In this exercise, we have the following equation:
[tex]y=-(x-2)^2+3[/tex]
From here, we can conclude that:
[tex]Leading \ coefficient: \ -1 \\ \\ Vertex: \ (2,3)[/tex]
Since the leading coefficient is less than zero, the parabola open downward. So, the graph is shown below and the vertex has been indicated.
Learn more:
Finding leading coefficient: https://brainly.com/question/1469367
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