Answer:
The answer is the option A.
x=(5±[tex]\sqrt33[/tex])/4
Step-by-step explanation:
The quadratic formula has the following form for a quadratic equation ax²+bx+c:
x=(-b±[tex]\sqrt{b^{2} -4ac}[/tex]))/(2a)
We apply the quadratic formula and we obtain:
x=(-(-5)±[tex]\sqrt{5^{2} -4(2)(-1)}[/tex]))/(2(2))
x=(-(-5)±[tex]\sqrt{25 +8}[/tex]))/(4)
x=(-(-5)±[tex]\sqrt{33}[/tex]))/(4)
