Linda Barnes has learned from prior studies that one out of five applicants gets admitted to top MBA programs in the country. She wishes to construct her own 95% confidence interval for the acceptance rate in top MBA programs. How large a sample should she take if she does not want the acceptance rate of the sample to deviate from that of the population by more than seven percentage points?

Respuesta :

Answer: 126

Step-by-step explanation:

As per given , we have

Prior Population proportion : [tex]p=\dfrac{1}{5}=0.2[/tex]

Significance level : [tex]\alpha=1-0.95=0.05[/tex]

Critical value for 95% confidence interval (using the z-value table) = [tex]z_{\alpha/2}=1.96[/tex]

Margin of error (maximum error): [tex]E=7\%=0.07[/tex]

Formula to find the sample size :

[tex]n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\ n=0.20(1-0.20)(\dfrac{1.96}{0.07})^2\\\\ n=125.44\approx126[/tex]

Therefore , the required minimum sample size = 126

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