WILL GIVE BRAINLIEST!
Let a and b be real numbers, where a ≠ b ≠ 0 . Which of the following functions could represent the graph on the right?

f(x) = x (x – a)(x – b)^2

f(x) = (x – a)(x – b)^2

f(x) = x(x – a)^3 (x – b)

f(x) = x^2(x – a) ^2(x – b)^2


WILL GIVE BRAINLIESTLet a and b be real numbers where a b 0 Which of the following functions could represent the graph on the right fx x x ax b2 fx x ax b2 fx x class=

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Answer:

  f(x) = x (x – a)(x – b)^2

Step-by-step explanation:

The graphed function is of 4th degree. There only one answer choice that is 4th-degree—the one listed above.

You know the degree is even because both end behaviours have the same sign.

You know there is one double root and two single roots because of the number of zero crossings and the zero "touch". That is, the total number of roots is 4.

These observations are sufficient to identify the correct answer choice.

_____

You can also observe that one of the single roots is x=0, so x (to the first power) will be a factor. That eliminates the 2nd and 4th choices. You know there is an even-multiplicity root at x < 0, because the graph touches, but does not cross the x-axis. That eliminates the 3rd choice.

(x-axis labelling is inconsistent, so we cannot tell the actual root values.)

Answer:

 f(x) = x (x – a)(x – b)^2

Step-by-step explanation:

pls give brnliest i know its right bcs i took the quiz

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