Answer:
7.92 m/s
Explanation:
[tex]m_1[/tex] = Mass of raindrop = [tex]45m_2[/tex]
[tex]m_2[/tex] = Mass of mosquito
[tex]u_1[/tex] = Initial Velocity of raindrop = 8.1 m/s
[tex]u_2[/tex] = Initial Velocity of mosquito = 0 m/s
[tex]v[/tex] = Velocity of center of mass
For elastic collision
[tex]m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{45m_2\times 8.1 + m_2\times 0}{45m_2 + m_2}\\\Rightarrow v=\frac{364.5m_2}{46m_2}\\\Rightarrow v=7.92\ m/s[/tex]
Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s