Thickness measurements of a coating process are made to the nearest hundredth of a millimeter. The thickness measurements are uniformly distributed with values 0.15, 0.16, 0.17, 0.18, and 0.19. Determine the mean and variance of the coating thickness for this process.

Respuesta :

Answer:

Mean = 0.17

Variance = 0.0068

Step-by-step explanation:

It is given in the question that the data is uniformly distributed, therefore the mean will be calculated using the formula

Mean = [tex]\frac{a+b}{2}[/tex]

here, a is the minimum value and b is the maximum value

for the data: 0.15, 0.16, 0.17, 0.18, and 0.19

a = 0.15

b = 0.19

Therefore,

Mean = [tex]\frac{0.15+0.19}{2}[/tex]

or

Mean = [tex]\frac{0.34}{2}[/tex]

or

Mean = 0.17

Variance = [tex]\frac{(b-a+1)^2-1}{12}[/tex]

or

Variance = [tex]\frac{(0.19-0.15+1)^2-1}{12}[/tex]

or

Variance = 0.0068

Q&A Education