Answer:
[tex]v=0.8m/s[/tex]
Explanation:
To solve the problem, we can use collisions theory from classical physics
If we analyze the players before and after the collision we got:
[tex]p_{1}=p_{2}[/tex]
Since the cling together
[tex]m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v[/tex]
From the exercise we know that the first player is 95.0 kg and has an initial velocity of 6.00 m/s, while the second player is 115 kg and has an initial velocity of –3.50 m/s.
[tex]v=\frac{m_{1}v_{1}+m_{2}v_{2}}{(m_{1}+m_{2})}=\frac{(95kg)(6m/s)+(115kg)(-3.5m/s)}{(95+115)kg}[/tex]
[tex]v=0.797m/s=0.8m/s[/tex]
