Explanation:
It is given that,
Weight of a woman, W = 130 lb
The area of the heel, [tex]A=0.5\ in^2[/tex]
The force acting per unit of area is called the pressure exerted on the underlying surface.
(a) Weight in newton, W = 578.26 N
Area of the heel, [tex]A=3.22\times 10^{-4}\ m^2[/tex]
Pressure, [tex]P=\dfrac{F}{A}[/tex]
[tex]P=\dfrac{578.26\ N}{3.22\times 10^{-4}\ m^2}[/tex]
[tex]p=1795838.50\ Pa[/tex]
or
P = 1795 kPa
(b) Since, [tex]1\ Pascals=9.86\times 10^{-6}\ atm[/tex]
[tex]1795838.50\ Pascals=17.72\ atm[/tex]
(c) [tex]P=\dfrac{F}{A}[/tex]
[tex]P=\dfrac{130\ lb}{0.5\ in^2}[/tex]
[tex]p=260\ lb/in^2[/tex]
Hence, this is the required solution.
